Hydrocarbons MCQs with Answers
Which of the following is an example of an aromatic hydrocarbon?
Cyclohexane
Hexane
Hexene
Benzene
Explanation:Aromatic hydrocarbons are cyclic, planar compounds that exhibit resonance stabilization. Benzene (C₆H₆) is the classic example of an aromatic hydrocarbon, characterized by its delocalized pi electron system.
What is the IUPAC name for the compound CH₃CH(CH₃)CH₂CH₃?
Isopentane
n-Pentane
3-Methylbutane
2-Methylbutane
Explanation:The longest continuous carbon chain is four carbons (butane). There is a methyl group (-CH₃) attached to the second carbon when numbered from the end that gives the substituent the lowest possible number.
Which of the following represents an unsaturated hydrocarbon?
Propane
Cyclopentane
Methane
Butyne
Explanation:Unsaturated hydrocarbons contain carbon-carbon double or triple bonds. Butyne contains a carbon-carbon triple bond, making it an alkyne and thus unsaturated.
The IUPAC name for CH₂=CH-CH₂-CH₃ is:
But-1-ene
1-Butene
Butylene
Either a or b
Explanation:Both "But-1-ene" and "1-Butene" are acceptable IUPAC names for this compound. The longest chain contains four carbons, and the double bond starts at the first carbon.
Which type of hydrocarbon is characterized by a general formula of CₙH₂ₙ?
Alkynes
Alkanes
Aromatic hydrocarbons
Alkenes
Explanation:Alkenes are unsaturated hydrocarbons containing one carbon-carbon double bond, and their general formula is CₙH₂ₙ.
What is the correct IUPAC name for HC≡C-CH₂-CH₃?
1-Butyne
But-1-yne
Ethylacetylene
Both a and b
Explanation:The longest carbon chain containing the triple bond has four carbons, and the triple bond starts at the first carbon. Therefore, both "1-Butyne" and "But-1-yne" are correct IUPAC names.
A hydrocarbon with a ring structure, but lacking the special stability of benzene, is classified as:
Aromatic
Alkyne
Alkene
Aliphatic
Explanation:Cyclic aliphatic hydrocarbons (like cycloalkanes or cycloalkenes) have ring structures but do not possess the conjugated double bonds and resonance stability characteristic of aromatic compounds.
Which of the following alkanes has the IUPAC name 2,2,4-trimethylpentane?
(CH₃)₃CCH₂CH(CH₃)₂
CH₃CH(CH₃)CH₂C(CH₃)₃
(CH₃)₂CHCH₂CH(CH₃)CH₃
CH₃C(CH₃)₂CH₂CH(CH₃)₂
Explanation:The longest continuous carbon chain is five carbons (pentane). There are methyl groups at the 2nd (two methyls) and 4th positions, when numbering from the end that gives the lowest set of locants.
The term "aliphatic" in organic chemistry primarily refers to hydrocarbons that are:
Cyclic and conjugated
Containing a benzene ring
Only straight-chain compounds
Open-chain or cyclic, but not aromatic
Explanation:Aliphatic hydrocarbons are non-aromatic carbon compounds. They can be straight-chain, branched-chain, or cyclic, but they do not contain the delocalized pi electron system found in aromatic compounds.
Which step in a free radical substitution reaction involves the formation of new free radicals from existing ones?
Initiation
Termination
Combination
Propagation
Explanation:In the propagation step, a free radical reacts with a stable molecule to form a new stable molecule and a new free radical, thus continuing the chain reaction.
What type of bond cleavage occurs during the initiation step of a free radical halogenation of alkanes?
Heterolytic cleavage
Ionic cleavage
Polar cleavage
Homolytic cleavage
Explanation:The initiation step typically involves the homolytic cleavage of a halogen molecule (e.g., Cl₂ → 2Cl•) by UV light or heat, producing two free radicals, each retaining one electron from the shared pair.
In the free radical chlorination of methane, which species is responsible for abstracting a hydrogen atom from methane?
Chlorine molecule (Cl₂)
Methyl radical (•CH₃)
Hydrogen chloride (HCl)
Chlorine radical (Cl•)
Explanation:The chlorine radical (Cl•) is highly reactive and abstracts a hydrogen atom from methane (CH₄ + Cl• → •CH₃ + HCl) in a propagation step, forming a methyl radical.
Which of the following conditions is typically required to initiate the free radical halogenation of alkanes?
High pressure
Presence of a strong acid
Presence of a noble gas
UV light or high temperature
Explanation:Free radical reactions are initiated by providing energy (e.g., UV light or heat) to break a bond homolytically, usually a halogen-halogen bond, creating free radicals.
The reaction of ethane with chlorine in the presence of UV light primarily produces:
Ethylene
Ethyne
Benzene
Chloroethane
Explanation:In the free radical substitution of ethane with chlorine, a hydrogen atom is replaced by a chlorine atom, leading to the formation of chloroethane (CH₃CH₂Cl). Multiple substitutions can occur, but monochlorination is typically the first step.
In the free radical mechanism for the halogenation of alkanes, what is the role of UV light or heat?
To break C-H bonds heterolytically
To accelerate the termination steps
To make the alkane more polar
To provide energy for the homolytic cleavage of the halogen molecule
Explanation:UV light or heat provides the activation energy necessary to break the relatively weak halogen-halogen bond homolytically, forming highly reactive halogen free radicals that initiate the reaction.
Which of the following best describes a free radical?
An ion with a positive charge
A molecule with a lone pair of electrons
An atom with a full octet of electrons
A species with an unpaired electron
Explanation:A free radical is an atom, molecule, or ion that has at least one unpaired valence electron. This unpaired electron makes free radicals highly reactive.
The general mechanism of free radical substitution in alkanes involves three main steps. What is the correct order of these steps?
Propagation, Initiation, Termination
Initiation, Termination, Propagation
Termination, Propagation, Initiation
Initiation, Propagation, Termination
Explanation:The reaction starts with Initiation (formation of radicals), continues with Propagation (radicals react to form new radicals and products), and ends with Termination (radicals combine to form stable molecules).
Why are alkanes generally unreactive towards polar reagents but readily undergo free radical substitution?
Because they are highly polar molecules.
Because they have delocalized pi electrons.
Because they readily form carbocations.
Because C-C and C-H bonds are non-polar
Explanation:The C-C and C-H bonds in alkanes are strong and essentially non-polar, so they are not easily attacked by electrophiles or nucleophiles (polar reagents). However, they can undergo homolytic cleavage, especially of C-H bonds, to form radicals which then participate in free radical substitution reactions.
What is the approximate bond angle around each carbon atom in ethene (C₂H₄)?
Explanation:Each carbon atom in ethene is sp² hybridized, which leads to a trigonal planar geometry around each carbon and approximate bond angles of 120°.
The double bond in ethene consists of which types of bonds?
Two sigma (σ) bonds
Two pi (π) bonds
One sigma (σ) and two pi (π) bonds
One sigma (σ) and one pi (π) bond
Explanation:A carbon-carbon double bond is formed by the overlap of sp² hybrid orbitals to form a sigma (σ) bond, and the sideway overlap of unhybridized p orbitals to form a pi (π) bond.
Which statement best describes the reactivity of alkenes compared to alkanes?
Alkenes are less reactive due to their stable single bonds.
Alkenes are more reactive due to the presence of a strong pi (π) bond.
Alkenes have similar reactivity to alkanes.
Alkenes are more reactive due to the exposed and weaker pi (π) bond.
Explanation:The pi (π) bond in alkenes is weaker and more exposed than sigma bonds, making it susceptible to electrophilic attack. This makes alkenes generally more reactive than alkanes, which primarily undergo substitution reactions.
Compounds that have the same molecular formula but different structural formulas are known as:
Homologs
Allotropes
Polymers
Isomers
Explanation:Isomers are compounds that have the same molecular formula but differ in the arrangement of atoms. Structural isomers (or constitutional isomers) specifically have different connectivity of atoms.
Which type of isomerism involves differences in the arrangement of atoms within the molecule due to restricted rotation around a double bond?
Chain isomerism
Position isomerism
Functional group isomerism
Geometric (cis-trans) isomerism
Explanation:Geometric isomerism (a type of stereoisomerism) arises when there is restricted rotation around a bond (like a carbon-carbon double bond) and different groups are attached to the carbons of the double bond, leading to distinct spatial arrangements (cis or trans).
Dehydration of ethanol (CH₃CH₂OH) using concentrated H₂SO₄ primarily yields:
Ethane
Ethyne
Dimethyl ether
Ethene
Explanation:Dehydration of alcohols involves the removal of a water molecule. In the case of ethanol, under the influence of a strong dehydrating agent like concentrated sulfuric acid, ethene (CH₂=CH₂) is formed.
Dehydrohalogenation of an alkyl halide (RX) involves the removal of:
Hydrogen and oxygen
Halogen only
Hydrogen only
Hydrogen and a halogen
Explanation:Dehydrohalogenation is an elimination reaction where a hydrogen atom from one carbon and a halogen atom from an adjacent carbon are removed, typically in the presence of a strong base, to form an alkene.
The addition of hydrogen to ethene in the presence of a catalyst like Ni or Pt is called:
Halogenation
Hydration
Polymerization
Hydrogenation
Explanation:Hydrogenation is the addition of hydrogen (H₂) across a double bond, typically in the presence of a metal catalyst, converting an alkene into an alkane.
According to Markovnikov's Rule, when an unsymmetrical reagent like HBr adds to an unsymmetrical alkene, the hydrogen atom attaches to the carbon atom that:
Has fewer hydrogen atoms already
Is more substituted
Is bonded to the bromine atom
Has more hydrogen atoms already
Explanation:Markovnikov's Rule states that in the electrophilic addition of HX (where X is a halogen) to an unsymmetrical alkene, the hydrogen atom adds to the carbon atom of the double bond that already has a greater number of hydrogen atoms.
The reaction of ethene with water in the presence of an acid catalyst (H₂SO₄) to form ethanol is known as:
Hydrogenation
Halogenation
Polymerization
Hydration
Explanation:Hydration is the addition of water across a double bond, typically catalyzed by an acid, leading to the formation of an alcohol.
What is the product formed when ethene reacts with bromine water (Br₂/H₂O)?
1,2-Dibromoethane
Bromoethane
Ethane
2-Bromoethanol
Explanation:This is an example of halohydration. When ethene reacts with bromine water, the bromine adds to one carbon and a hydroxyl group (-OH) from water adds to the other carbon of the double bond, resulting in 2-bromoethanol.
The polymerization of ethene leads to the formation of:
Polypropylene
Polystyrene
Polyvinyl chloride
Polyethylene
Explanation:Polymerization is a process where many small monomer units join together to form a large polymer molecule. When ethene (ethylene) monomers polymerize, they form polyethylene.
Which of the following is an example of a structural isomer of but-1-ene?
Butane
Cyclobutane
But-2-ene
2-Methylpropene
Explanation:Structural isomers have the same molecular formula but different connectivity of atoms. But-1-ene (C₄H₈) and 2-methylpropene (C₄H₈) both have the formula C₄H₈ but differ in the arrangement of their carbon atoms and double bond position. But-2-ene is a positional isomer, not a structural isomer of but-1-ene in the context of different carbon skeletons.
When ethene undergoes halogenation with Cl₂, what is the primary product?
Chloroethane
1,1-Dichloroethane
2-Chloroethanol
1,2-Dichloroethane
Explanation:Halogenation of alkenes is an addition reaction where halogen atoms add across the double bond. For ethene and chlorine, the product is 1,2-dichloroethane.
The addition of HCl to ethene yields:
Ethane
Chloroethene
1,2-Dichloroethane
Chloroethane
Explanation:This is a hydrohalogenation reaction. The hydrogen atom adds to one carbon of the double bond and the chlorine atom adds to the other, resulting in chloroethane.
Why do alkenes typically undergo addition reactions rather than substitution reactions?
Because they are saturated compounds.
Because the π bond is strong and resistant to cleavage.
Because they readily form free radicals.
Because the π electrons are exposed and easily attacked by electrophiles.
Explanation:The pi (π) bond in alkenes contains loosely held, exposed electrons that act as nucleophiles and are readily attacked by electrophiles, leading to addition across the double bond.
Which of the following catalysts is commonly used for the hydrogenation of alkenes?
Zinc
Sodium hydroxide
Sulfuric acid
Platinum or Palladium or Nickel
Explanation:Hydrogenation of alkenes typically requires a metal catalyst such as platinum, palladium, or nickel to facilitate the addition of hydrogen across the double bond.
The structural isomerism exhibited by but-1-ene and 2-methylpropene is an example of:
Position isomerism
Functional group isomerism
Metamerism
Chain isomerism
Explanation:But-1-ene has a straight four-carbon chain, while 2-methylpropene has a branched three-carbon chain. They have the same molecular formula (C₄H₈) but different carbon skeletons, which defines chain isomerism.
What type of reaction is the formation of ethanol from ethene and steam in the presence of an acid catalyst?
Dehydrogenation
Dehydration
Substitution
Hydration
Explanation:This is the direct addition of water to the alkene across the double bond, resulting in an alcohol. This process is called hydration.
Which reagent is used for the preparation of an alkene from a vicinal dihalide?
Aqueous KOH
Alcoholic KOH
Conc. H₂SO₄
Zinc dust
Explanation:Vicinal dihalides undergo dehalogenation when treated with zinc dust, where the two halogen atoms are removed, forming an alkene. This is a common method for alkene preparation.
According to molecular orbital theory, the benzene molecule consists of a planar hexagonal ring formed by:
sp³ hybridized carbon atoms
sp hybridized carbon atoms
Unhybridized carbon atoms
sp² hybridized carbon atoms
Explanation:Each carbon atom in benzene is sp² hybridized. This leads to a planar hexagonal structure where each carbon forms three sigma bonds (two with adjacent carbons and one with a hydrogen atom).
The delocalization of pi electrons in benzene results in a special stability known as:
Inductive effect
Hyperconjugation
Aromaticity
Resonance energy
Explanation:The extra stability of benzene due to the delocalization of its pi electrons is quantified as resonance energy. This energy makes benzene significantly more stable than a hypothetical cyclohexatriene. While aromaticity is the property, resonance energy is the result of this delocalization contributing to stability.
Compared to alkenes, benzene primarily undergoes:
Addition reactions
Elimination reactions
Rearrangement reactions
Substitution reactions
Explanation:Despite having double bonds, benzene's aromatic stability is preserved by substitution reactions (specifically electrophilic aromatic substitution) where a hydrogen atom is replaced, rather than addition reactions which would disrupt the delocalized pi system.
Which of the following is an example of an addition reaction of benzene?
Nitration
Sulfonation
Halogenation
Hydrogenation
Explanation:While benzene primarily undergoes substitution, it can undergo addition reactions under specific harsh conditions, such as hydrogenation (addition of hydrogen) to form cyclohexane, which breaks the aromaticity.
The mechanism of electrophilic substitution in benzene involves the initial attack of an electrophile on the benzene ring, forming a:
Carbanion
Free radical
Zwitterion
Carbocation
Explanation:In electrophilic aromatic substitution, the electrophile attacks the pi electron cloud of the benzene ring, forming a resonance-stabilized carbocation intermediate, also known as a sigma complex or arenium ion.
In the nitration of benzene, the electrophile that attacks the benzene ring is:
Explanation:The electrophile for nitration is the nitronium ion (NO₂⁺), which is generated by the reaction of nitric acid with sulfuric acid (HNO₃ + 2H₂SO₄ → NO₂⁺ + H₃O⁺ + 2HSO₄⁻).
What is the catalyst commonly used in the electrophilic halogenation of benzene (e.g., chlorination or bromination)?
Ni or Pt
Conc. H₂SO₄
UV light
FeCl₃
Explanation:Electrophilic halogenation of benzene requires a Lewis acid catalyst (like FeCl₃ for chlorination or FeBr₃ for bromination) to polarize the halogen molecule and generate a more powerful electrophile.
The Friedel-Crafts alkylation reaction of benzene introduces an alkyl group. What is the typical catalyst for this reaction?
NaOH
KMnO₄
H₂O
Anhydrous AlCl₃
Explanation:Anhydrous aluminum chloride (AlCl₃) is the most common Lewis acid catalyst used in Friedel-Crafts alkylation to generate the electrophilic carbocation from an alkyl halide.
The sulfonation of benzene involves the introduction of a -SO₃H group. What is the active electrophile in this reaction?
Explanation:The active electrophile for sulfonation is sulfur trioxide (SO₃), which is present in fuming sulfuric acid or generated from concentrated sulfuric acid.
Which of the following statements about benzene is FALSE?
All C-C bond lengths in benzene are identical.
Benzene is more stable than a hypothetical cyclohexatriene.
Benzene has a planar structure.
Benzene readily undergoes addition reactions.
Explanation:This statement is false. Benzene preferentially undergoes substitution reactions to maintain its aromatic stability, unlike typical alkenes which readily undergo addition reactions.
When methylbenzene (toluene) undergoes nitration, the incoming nitro group (-NO₂) is directed primarily to which positions?
Meta positions
Only ortho position
Only para position
Ortho and para positions
Explanation:The methyl group (-CH₃) is an activating group and an ortho/para director in electrophilic aromatic substitution due to its electron-donating effect via hyperconjugation.
What is the product formed when benzene reacts with an acyl chloride (RCOCl) in the presence of anhydrous AlCl₃?
Alkylbenzene
Carboxylic acid
Phenol
Phenylketone
Explanation:This is a Friedel-Crafts acylation reaction. An acyl group (RCO-) is introduced onto the benzene ring, forming a ketone where one of the groups attached to the carbonyl is a phenyl group.
Which of the following groups is a deactivating and meta-directing group in electrophilic aromatic substitution?
-OH (hydroxyl)
-NH₂ (amino)
-CH₃ (methyl)
-NO₂ (nitro)
Explanation:The nitro group (-NO₂) is a strong electron-withdrawing group, which deactivates the benzene ring towards electrophilic attack and directs incoming electrophiles to the meta position.
When benzene undergoes Friedel-Crafts acylation, what is the key advantage over alkylation in terms of product control?
Acylation leads to multiple substitutions easily.
Acylation products can be easily deacylated.
Acylation is reversible.
Acylation does not lead to carbocation rearrangements.
Explanation:Friedel-Crafts alkylation involves carbocations, which can undergo rearrangements, leading to mixtures of products. Friedel-Crafts acylation, on the other hand, involves stable acylium ions, which do not rearrange, thus providing better control over the product.
Which of the following compounds will undergo electrophilic substitution faster than benzene?
Nitrobenzene
Chlorobenzene
Benzoic acid
Toluene
Explanation:Toluene has a methyl group (-CH₃), which is an electron-donating group. Electron-donating groups activate the benzene ring towards electrophilic substitution by increasing electron density, making the reaction faster than with benzene itself.
The conversion of benzene to cyclohexane under specific conditions is an example of:
Electrophilic substitution
Free radical substitution
Oxidation
Catalytic hydrogenation
Explanation:The addition of hydrogen to benzene (hydrogenation) in the presence of a catalyst (e.g., Ni, Pt) converts it into cyclohexane, breaking the aromatic system and forming an aliphatic cyclic compound.
What is the product of the reaction between benzene and Cl₂ in the presence of UV light and no catalyst?
Chlorobenzene
1,2-Dichlorobenzene
Benzyl chloride
Hexachlorocyclohexane
Explanation:In the absence of a Lewis acid catalyst, and under UV light, benzene can undergo free radical addition reactions, leading to the addition of six chlorine atoms across the ring, forming hexachlorocyclohexane (e.g., Lindane).
Which of the following is an ortho/para directing group and an activating group?
Explanation:Methoxy group (-OCH₃) is an electron-donating group via resonance, which activates the ring and directs incoming electrophiles to the ortho and para positions.
The sulfonation of benzene is reversible. What conditions favor the desulfonation ?
Reaction with strong base
Reaction with oxidizing agent
Reaction with reducing agent
Heating with dilute acid
Explanation:Sulfonation is reversible. Heating benzenesulfonic acid with steam or dilute aqueous acid can reverse the reaction, removing the sulfonic acid group (removal of -SO₃H group) and regenerating benzene.
When an activating group is present on the benzene ring, the rate of electrophilic substitution reaction:
Decreases
Remains unchanged
Becomes zero
Increases
Explanation:Activating groups donate electron density to the benzene ring, making it more nucleophilic and thus more susceptible to attack by an electrophile, increasing the reaction rate.
Which of the following reagents is typically used for the Friedel-Crafts acylation of benzene?
An alkyl halide and AlCl₃
A halogen and FeX₃
Concentrated H₂SO₄
An acyl halide and AlCl₃
Explanation:Friedel-Crafts acylation involves the reaction of an acyl halide (RCOCl) or an acid anhydride with benzene in the presence of a Lewis acid catalyst like anhydrous AlCl₃.
The resonance hybrid structure of benzene explains that:
It has alternating single and double bonds.
It exists as two rapidly interconverting Kekulé structures.
It is a saturated compound.
All carbon-carbon bonds are identical and intermediate between single and double bonds.
Explanation:The resonance hybrid concept implies that the pi electrons are delocalized over the entire ring, resulting in all C-C bonds having equal length and character, intermediate between typical single and double bonds.
Which of the following reactions of benzene is also an electrophilic substitution reaction?
Reaction with H₂/Ni
Reaction with H₂O/H₂SO₄
Reaction with Cl₂/UV light
Reaction with Br₂/FeBr₃
Explanation:Reaction with Br₂ in the presence of a Lewis acid catalyst (FeBr₃) is electrophilic aromatic substitution (bromination), where a bromine atom substitutes a hydrogen atom on the benzene ring.
A strong deactivating group like -COOH (carboxyl) on a benzene ring will direct an incoming electrophile to which position?
Ortho
Para
Ortho and para
Meta
Explanation:Carboxyl groups (-COOH) are electron-withdrawing by resonance and inductive effects, strongly deactivating the ring and directing incoming electrophiles to the meta position.
The oxidation of benzene under typical conditions is difficult due to its:
High molecular weight
Planar structure
Non-polar nature
Aromatic stability
Explanation:The delocalized pi electron system and significant resonance energy of benzene make it very stable and resistant to oxidation under conditions that would typically oxidize alkenes.
Which of the following compounds is generally the most reactive towards electrophilic addition reactions?
Ethane
Ethyne
Benzene
Ethene
Explanation:Alkenes are generally more reactive than alkynes towards electrophilic addition. While alkynes have a triple bond, the sp hybridized carbons make the pi electrons more tightly held. Also, the carbocation formed from an alkyne is less stable than that from an alkene. Benzene undergoes substitution due to aromaticity, and alkanes are saturated.
The preparation of alkynes commonly involves which type of reaction?
Addition reaction
Substitution reaction
Rearrangement reaction
Elimination reaction
Explanation:Alkynes are typically prepared through double elimination reactions, such as the dehydrohalogenation of dihaloalkanes (vicinal or geminal) using strong bases.
Which statement best describes the acidity of terminal alkynes?
They are less acidic than alkanes and alkenes.
They are highly acidic, comparable to strong mineral acids.
They are neutral compounds.
They are more acidic than alkanes and alkenes.
Explanation:The carbon atom in the C-H bond of a terminal alkyne is sp hybridized, which means it has higher s-character (50%) than sp² (33%) or sp³ (25%). This higher s-character makes the carbon more electronegative, drawing electron density closer to the nucleus, and thus making the hydrogen more acidic and easier to remove as a proton.
The complete hydrogenation of acetylene in the presence of a catalyst like Ni or Pt yields:
Ethene
Methane
Butane
Ethane
Explanation:Complete hydrogenation of an alkyne (acetylene) involves the addition of two moles of hydrogen across the triple bond, converting it into a fully saturated alkane. Thus, ethyne becomes ethane.
Partial hydrogenation of alkynes to form cis-alkenes is achieved using which catalyst?
Ni/H₂
Na in liquid NH₃
Pt/H₂
Lindlar's catalyst
Explanation:Lindlar's catalyst (Pd/BaOS₄ + quinoline) is a poisoned palladium catalyst that allows for the selective partial hydrogenation of alkynes to cis-alkenes, preventing further reduction to alkanes.
According to Markovnikov's rule, the addition of HBr to propyne (CH₃C≡CH) will primarily yield:
1-Bromopropene
1,2-Dibromopropane
1-Propanol
2-Bromopropene
Explanation:In the hydrohalogenation of an unsymmetrical alkyne like propyne, the hydrogen atom adds to the carbon of the triple bond that has more hydrogen atoms (the terminal carbon), and the bromine adds to the more substituted carbon, resulting in 2-bromopropene.
The hydration of alkynes (e.g., ethyne) in the presence of H₂SO₄ and HgSO₄ typically forms:
Alcohols
Carboxylic acids
Alkenes
Aldehydes or ketones
Explanation:Hydration of alkynes in the presence of mercuric sulfate and sulfuric acid proceeds via an enol intermediate, which rapidly tautomerizes to a more stable carbonyl compound. Ethyne yields acetaldehyde (an aldehyde), while higher alkynes yield ketones.
Which of the following alkynes can react with ammoniacal silver nitrate solution (Tollens' reagent) to form a white precipitate?
CH₃-C≡C-CH₃ (2-Butyne)
CH₂=CH-C≡CH (Vinylacetylene)
CH₂=CH-CH=CH₂ (1,3-Butadiene)
CH₃-CH₂-C≡CH (1-Butyne)
Explanation:Terminal alkynes (those with a C≡C-H bond) have an acidic hydrogen atom that can be replaced by metal ions. 1-Butyne is a terminal alkyne and will react with Tollens' reagent to form a silver acetylide precipitate. Internal alkynes (like 2-Butyne) do not have this acidic hydrogen.
A reaction in which an atom or group of atoms is replaced by another atom or group of atoms in a molecule is known as a:
Addition reaction
Elimination reaction
Rearrangement reaction
Substitution reaction
Explanation:In a substitution reaction, one atom or group is taken out and another is put in its place, while the overall saturation of the molecule often remains the same (e.g., replacement of H in an alkane by a halogen).
Which type of reaction involves the joining of two or more molecules to form a single larger molecule, typically by breaking a pi bond?
Substitution reaction
Elimination reaction
Polymerization reaction
Addition reaction
Explanation:An addition reaction involves the combination of two or more molecules to form a single product. This typically occurs across unsaturated bonds (double or triple bonds), where the pi bond breaks and new sigma bonds are formed. Polymerization is a specific type of addition reaction where many monomers add to form a very large molecule.
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