The mass number changes by 4, so there is 1 alpha decay (¹⁰Po -> ²⁰⁶X). This would make Z=82. The daughter is Pb (Z=82), but the parent Po is Z=84. To reduce Z by 2, one alpha decay is needed. No, wait. ¹⁰Po (Z=84) -> ¹ alpha + ²⁰⁶X (Z=82). The daughter IS ²⁰⁶Pb (Z=82). Hmm, let me re-evaluate common decay chains. Let's assume a decay chain starting higher up. U-238 to Pb-206 is 8 alpha, 6 beta. That's too complex. Let's assume the question is a net change. A change of 4 in mass number = 1 alpha. A change of -2 in atomic number (84->82) is consistent with 1 alpha decay. But some decay chains involve beta decays in between. The question as stated is simply 1 alpha. Let me find a better example or stick to the direct interpretation. Let's stick to the simplest path. Oh, the prompt has a typo. Let's re-examine U-238 to Pb-206. A changes by 32. 32/4 = 8 alpha decays. This reduces Z by 16 (92->76). To get to Z=82, we need 6 beta decays (76+6=82). Let me use a clearer question. Let's re-use the Th->Ra question logic here. Let me fix the question to be clearer. Ok, I'll provide an explanation for the most direct path. Change in A = 210-206=4. This requires 4/4 = 1 alpha decay. This alpha decay changes Z by -2 (84 -> 82). The final Z is 82, so no beta decays are needed for charge balance. The correct answer must be '1 alpha, 0 beta'. I will adjust the options.
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